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llOrd

integer llOrd(string value, integer index)

Returns the unicode value of the indicated character in the string.

Parameters

value (string): The string to convert to Unicode.
index (integer): Index of character to convert to unicode.

Technical Details

Return Type: integer
Energy: 10

default
{
    touch_start(integer total_number)
    {
        string test_string = "The quick brown fox jumped over the lazy dog";
        list test_list = [];
        string test_string2 = "";

        integer index;
        integer ord;
        for (index = 0; index < llStringLength(test_string); ++index)
        {
            ord = llOrd(test_string, index);
            test_list = test_list + [ ord ];
        }

        string char;
        for (index = 0; index < llGetListLength(test_list); ++index)
        {
            ord = llList2Integer(test_list, index);
            char = llChar(ord);
            test_string2 = test_string2 + char;
        }

        llSay(0, "\"" + test_string + "\" -> [" +
            llDumpList2String(test_list, ", ") + "] -> \"" + test_string2 + "\"");
    }
}

This example demonstrates converting all characters in a string to their ordinal values, storing them in a list, then converting them back to characters to reconstruct the original string.

Notes

Returns the UTF-32 value of the character at the specified index
If the index is outside the bounds of the string, this function returns 0
This function is the inverse of llChar, which converts an ordinal value back to a character

See Also

llChar - Convert an ordinal into a character
llHash - Calculate a 32-bit hash for a string
llStringLength - Get the length of a string